LeetCode 184 部门工资最高的员工

表: Employee

+--------------+---------+
| 列名          | 类型    |
+--------------+---------+
| id           | int     |
| name         | varchar |
| salary       | int     |
| departmentId | int     |
+--------------+---------+
id是此表的主键列。
departmentId是Department表中ID的外键。
此表的每一行都表示员工的ID、姓名和工资。它还包含他们所在部门的ID。

表: Department

+-------------+---------+
| 列名         | 类型    |
+-------------+---------+
| id          | int     |
| name        | varchar |
+-------------+---------+
id是此表的主键列。
此表的每一行都表示一个部门的ID及其名称。

编写SQL查询以查找每个部门中薪资最高的员工。
按 任意顺序 返回结果表。
查询结果格式如下例所示。

示例 1:

输入:
Employee 表:
+----+-------+--------+--------------+
| id | name  | salary | departmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Jim   | 90000  | 1            |
| 3  | Henry | 80000  | 2            |
| 4  | Sam   | 60000  | 2            |
| 5  | Max   | 90000  | 1            |
+----+-------+--------+--------------+
Department 表:
+----+-------+
| id | name  |
+----+-------+
| 1  | IT    |
| 2  | Sales |
+----+-------+
输出:
+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Jim      | 90000  |
| Sales      | Henry    | 80000  |
| IT         | Max      | 90000  |
+------------+----------+--------+
解释:Max 和 Jim 在 IT 部门的工资都是最高的,Henry 在销售部的工资最高。

解题:

SELECT d.name 'Department', e.name 'Employee', e.salary 'Salary' FROM Employee e
INNER JOIN (SELECT MAX(salary) salary, departmentId FROM Employee GROUP BY departmentId) t ON t.salary = e.salary AND t.departmentId = e.departmentId
INNER JOIN Department d ON d.id = e.departmentId;

官方解答:

1.使用 JOIN 和 IN 语句

SELECT Department.name 'Department', Employee.name 'Employee', Employee.salary 'Salary' From Employee
JOIN Department ON Department.id = Employee.departmentId
WHERE (Employee.Salary, departmentId) IN (SELECT MAX(salary), departmentId FROM Employee GROUP BY departmentId);

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