LeetCode 181 超过经理收入的员工

表：Employee

表：Employee 

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
Id是该表的主键。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。

编写一个SQL查询来查找收入比经理高的员工。

以 任意顺序 返回结果表。

查询结果格式如下所示。

示例 1:

输入: 
Employee 表:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
输出: 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
解释: Joe 是唯一挣得比经理多的雇员。

解答：

SELECT a.name AS 'Employee' FROM Employee a, Employee b WHERE a.managerId = b.id AND a.salary > b.salary;

官方解答：

1.使用where语句

SELECT a.Name AS 'Employee'
FROM Employee AS a, Employee AS b
WHERE a.ManagerId = b.Id AND a.Salary > b.Salary;

2.使用JOIN语句

SELECT a.NAME AS Employee
FROM Employee AS a JOIN Employee AS b ON a.ManagerId = b.Id AND a.Salary > b.Salary;